In fig 10.11 if tp and tq
WebExercise 10.2 Question 2 Class 10In Fig. 10.11, if TP and TQ are the two tangents to a circle with center O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) ... Exercise 10.2 Question 2... WebCHAPTER10 SinusoidalSteady-StateAnalysis 421 REVIEW QUESTIONS 10.1 The voltage V o across the capacitor in Fig. 10.43 is: (a) 5 0 V (b) 7.071 45 V (c) 7.071 −45 V (d) 5 −45 V 1 Ω + − Vo − 10 0° V –j1 Ω Figure10.43 For Review Question 10.1. 10.2 The value of the current I
In fig 10.11 if tp and tq
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WebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with cent... It is given that, ∠POQ =110° Since, the Iangent at any point of a circle is perpendicular to the radius through the point of contact. ∴ ∠OPT = 90° and ∠OQT = 90° Now, in quadrilateral POQT. ∠POQ + ∠OQT + ∠PTQ + ∠OPT = 360° (angle sum property of quadrilateral) WebOct 30, 2024 · In Fig. 10.11, if TP and TQ are the two tangents to a circle with Centre O so that angle POQ = 110°, then angle PTQ is equal to – Tiwari Academy Discussion. Home / …
Web. In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to A. 60° B. 70° C. 80° D. 90° Best Answer Solution: (B) is correct. Given, TP and TQ are tangents. Therefore, radius drawn to these tangents will be perpendicular to the tangents. Thus, OP ⊥ TP and OQ ⊥ TQ ∠OPT = 90ᵒ ∠OQT = 90ᵒ WebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠POQ = 110°, then ∠PTQ is equal to CBSE Circles Class 10 Maths NCERT In Fig. 10.11, if TP …
WebMar 22, 2024 · In figure, if TP and TQ are the two tangents to a circle with centre O so that POQ = 110 , then PTQ is equal to 60 (B) 70 (C) 80 (D) 90 Given POQ = 110 Here TP is a … WebIn Fig. 10.11 , if TP and TQ are the two tangents to a circle with centre O so that ∠POQ=110∘. then ∠PTQis equal to (A)60∘(C) 80∘B) 70∘(D)90Fig. 10.1 Open in App …
WebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90° Fig. 10.11 296 Views Answer A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is : (a) 12 cm (b) 13 cm (c) 8.5 cm (d)
WebJan 10, 2012 · Answer to Solved Calculate current I, in the circuit of Fig. 10.11. Engineering; Electrical Engineering; Electrical Engineering questions and answers composite volume worksheets grade 5Web12 contract might be guilty of misrepresentation (whether negligent or willful) or being unworthy or incompetent to act as a real estate broker, both violations of License Law … echigoya hobby torranceWebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90° Fig. 10.11 296 Views A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is : (a) 12 cm (b) 13 cm (c) 8.5 cm (d) e chi h twitterWebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠POQ=110∘, then ∠PTQ is equal to. (A) 60∘. (B) 70∘. (C) 80∘. (D) 90∘. Q. In the given figure, if TP and … composite utility boxesWebOct 30, 2024 · In Fig. 10.11, if TP and TQ are the two tangents to a circle with Centre O so that angle POQ = 110°, then angle PTQ is equal to. 2; Poll Results. 0% (A) 60° 100% (B) 70° ( 1 voter ) 0% (C) 80° 0% (D) 90° Based On 1 Vote. Participate in … composite vs acrylic bathtubhttp://coccweb.cocc.edu/bemerson/public_html/engineering/classes/engr202/engr202hw/documents/CH10probs.pdf echigo onsenWebFeb 19, 2024 · In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90° Solution: The tangent at any point of a circle is perpendicular to the radius at the point of contact. composite vs compound key